#KA AP Chem
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studentbyday · 2 years ago
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Molecular and ionic compound structure and properties Pt. 1
Types of chemical bonds - really a spectrum of bonds
All these occur b/c atoms are constantly moving and colliding unless at absolute 0. Goal of intramolecular bonds is to obtain full valence octets or full valence shells.
Ionic bonds - transfer of electron(s) from 1 atom to another b/c of very big difference in electronegativity b/t the atoms involved (1 has high electronegativity, other has low electronegativity), anion + cation = attracted to each other → electrically neutral compound, usually occurs between metal (b/c it typically forms cations) and nonmetal (b/c it typically forms anions)
Covalent bonds - sharing of electron(s) b/t atoms, sometimes equal sharing (non-polar), other times unequal sharing (polar), usually occurs between nonmetals that aren’t noble gases aka that don’t have full valence shells or full valence octets (same nonmetal element or not)
If bond is b/t same element, it’s non-polar b/c they have the same electronegativity
If bond is b/t different elements b/t w/ same electronegativity, it’s non-polar
If 1 element has a higher electronegativity than the other, but not enough of an electronegativity difference to cause a transfer of electron(s), it forms a polar bond
Covalent bonds tend to occur b/t elements w/ a range of relatively high electronegativities, i.e. nonmetals
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Metallic bonds - metal atoms’ valence electrons are loosely held b/c they all have low electronegativity, not fixed to a single atom, so when metal atoms are put together, you can imagine each atom donating electron(s) to form a “sea of electrons and metal cations”. This electrostatic attraction b/t metal cations and the sea of electrons gives metals their unique properties like electrical conductivity (b/c electrons are free to move), malleability (can bend it easily) and ductility (can roll into wires easily).
Stated another way, metallic bonds occur b/t atoms w/ similar, low electronegativities, i.e. metals.
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Metalloids have properties b/t metals and nonmetals, e.g. semiconductivity
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Intramolecular force and potential energy
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Bond length aka internuclear distance = the distance b/t the centers/nuclei of the atoms in a diatomic molecule
For bonded atoms, you have the equilibrium bond length, which is stable - the bond length at which you have the minimum potential energy (this is a negative number, e.g. -432 kJ/mol for diatomic hydrogen)
Expected internuclear distance for diatomic molecules at standard temperature and pressure
If you pull the atoms apart, you increase the bond length and therefore the potential energy from this low point, and if you keep pulling them apart, potential energy increases until it approaches 0 potential energy - the potential energy at which the atoms are no longer bonded together or associated w/ each other. This occurs because the Coulomb forces b/t them gets weaker and weaker the further you pull them apart.
Bond energy is the amount of energy you need to put in to break the bond b/t the atoms (e.g. 432 kJ/mol for diatomic hydrogen)
The higher the order of the bond (i.e. increasing from single to double to triple bonds), the larger its bond energy
If you push the atoms closer together, you decrease the bond length, which increases the potential energy from this low point - higher than 0 potential energy if you keep pushing them together. This increase in potential energy is due to increased repulsion b/t the electrons (negative charges) and the positive charges (protons in nucleus).
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Identifying diatomic molecules’ potential energy curves: Min. potential energy is a function of how small the atomic radii are and order of the bond
The smaller the radii, the closer the nuclei will be, so smaller equilibrium bond length
E.g. looking at periodic table, H has the smallest atomic radius, so it makes sense that H2′s internuclear distance is the smallest; but O has slightly smaller atomic radius than N, so based on bond length alone, you’d think that the salmon-colored curve is O2′s and the purple is N2′s b/c the salmon-colored curve has a slightly smaller internuclear distance. But in general, conclusions from bond order (differences in bond energy) trump conclusions from atomic radii (differences in bond length/internuclear distance). In this case, for e.g., N2′s triple bond pushes the N atoms closer together even if they might be a little bit bigger in radius than the O atoms.
The higher the order of the bond, the closer together the atoms will be, so smaller equilibrium bond length, and the higher the bond energy will be, so the more negative the min. potential energy
E.g. based on bond order, H2 has a single covalent bond, so it’s got the lowest bond energy; O2 has a double covalent bond, so it’s got a bond energy greater than H2 but less than N2 which has a triple covalent bond; N2 therefore has the highest bond energy
Lattice energy (kJ/mol) = energy needed to separate ions in a crystal lattice (ionic compound structure) into individual gaseous ions (same concept as bond energy for covalent bonds)
Lattice = 3D structure of atoms/ions w/ repeating pattern
E.g. NaCl crystal lattice: (Na+ is smaller than Cl-, even if Na is on left of periodic table and the trend is to decrease atomic radius as you move right, b/c Na loses an electron, so it loses a shell to obtain the electron configuration of Ne but w/ 1 more proton, so it has a really strong pull on its electrons, leading to a small ionic radius; meanwhile, Cl gains an electron and obtains the electron configuration of Ar but with 1 less proton, so it doesn’t have as strong a pull on its electrons compared to Na+, so it has a larger ionic radius)
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Depends on strength of interactions b/t cations and anions in the lattice, w/c can be estimated using Coulomb’s law: magnitude of the force  Fₑ = (q₁q₂)/r²
If the q’s charges are opposite, F is attractive; if the q’s charges are like, F is repulsive
Stronger interactions (stronger electrostatic force) occur b/t ions w/ larger charges and ions that have a smaller distance between each other
The stronger the interactions, the greater the lattice energy
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Structure of ionic solids
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Structure of metals and alloys
Alloys = mixtures of metal elements that maintain many of metals’ properties while creating other useful properties (e.g. stainless steel is much more resistant to corrosion than basic steel, basic steel is stronger than iron by itself)
Interstitial alloys - 1 atom has significantly larger radius than the other, e.g. steel = iron mixed w/ carbon w/c = much smaller than Fe and able to fit in gaps b/t iron atoms
Substitutional alloys - atoms involved have similar radius, e.g. brass = Cu + Zn w/c have similar atomic radii
Combo of both - e.g. stainless steel: Fe, C w/c is smaller than Fe, and Cr w/c is similar in radius to Fe
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444namesplus · 5 months ago
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studentbyday · 2 years ago
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photoelectron spectroscopy (PES)
PES uses the photoelectron effect which is basically describing how, when you zap a sample with photons of electromagnetic radiation (energy), you remove/eject its electrons. This uses the concept of ionization energy. Radiation = ionization energy + some extra. You're giving the sample enough energy to remove its electrons (ionization energy) and the extra energy gives the electron enough energy to move (kinetic energy). The electron's ionization energy is also called binding energy (because...???).
This is another way to say it: energy of photon = binding energy + kinetic energy of electron. Or abbreviated, Ephoton = BE + KEelectron
If you want to break it down further, energy of photon = Planck's constant*frequency of photon in Hertz = BE + KEelectron, or abbreviated: hv = BE + KEelectron
Solving for BE, that's BE = hv - KEelectron
PES creates a graph showing the number of electrons ejected on the y-axis vs their binding energy in electron volts eVeVstart text, e, V, end text) or megajoules (MJMJstart text, M, J, end text) per mole.onn the x-axis. How does it create this graph?
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High-energy photons, usually UV or X rays, hit a sample of free atoms or molecules (the photoelectric effect was originally described for metal surfaces but it also applies to free atoms or molecules), ejecting their electrons. These electrons' kinetic energies are measured with an energy analyser. A detector then counts how many electrons of a certain kinetic energy there are. From there, we can calculate the binding energies for the electrons ejected (called photoelectrons) using the equation above. Since the energy in the photons is constant for all electrons ejected, the greater the electron's kinetic energy, the less their binding energy, and vice versa.
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444namesplus · 1 year ago
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studentbyday · 2 years ago
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day 12/14 of chem & day 4/24 of reading
Wrote some more quantum behavior notes
Finished resonance and formal charge (KA AP Chem U2)
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studentbyday · 2 years ago
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I'm really happy with the Rilakkuma in the library aesthetic...but... If Rilakkuma is me, Rilakkuma is turning into the library version of lofi girl... Just stuck in the library... (Though mine is not a physical library, just KA's chemistry library XD). Ohhh there is sm info to cover. I was and still kinda am nervous for university chemistry, which is why I'm attempting to cover ALL of KA's chemistry library and AP Chem course in 14 days because that's about how much time I have between Winter term final season and summer classes... But...Idk if that's possible. Not panicking. Just...concerned.
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