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Here is a sudoku I made for the Fall MAA NJ-Section meeting last weekend, and now I want to share it here. The instructions explain everything needed but more details, a PDF, and the solution are on my blog at the following link:
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The clues of this new puzzle involve the Fibonacci sequence 0,1,1,2,3,5,8,13,21,… (also known as the Pingala or Virahanka sequence.)
Fill in the cells with the numbers 1 through 7 so each number is used twice and adjacent cells get different numbers. Whenever the sum of the numbers in adjacent cells is a Fibonacci number, that sum is given as a clue. This means if there is no clue on an edge, the sum of those numbers is -not- a Fibonacci number.
The idea to use this particular graph to make a puzzle came from Tom Edgar, the editor of Math Horizons magazine. Three more of these will appear in the next issue of that publication soon. More information about the puzzle, the solution, and a high quality PDF version, can be found at the following link:
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The clues here reveal whether the sum is less than, equal to, or greater than eleven. They also reveal whether the product is less than or greater than eleven. A solution, a PDF version, and some hints if you need help, can all be found on my blog here: https://quadratablog.blogspot.com/2024/10/eleven-sizedoku.html
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In this new Sudoku puzzle, the clues reveal when one number is either 2,3,4 or 5 times another. Further instructions are on the puzzle. The solution, more info, and a PDF version can be found at http://quadratablog.blogspot.com/2023/09/small-multiples-sudoku.html
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I feel spring is a good time for honeycomb puzzles. Instructions are on the picture and both the solution and a PDF version are available at my website: http://quadratablog.blogspot.com
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Here is one last 2023 Sudoku before we get too far into the year. All the clues are based on the numbers 2, 3, and 23. A solution and PDF version are at https://quadratablog.blogspot.com/2023/02/2023-reprise.html.
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Here's a Sudoku I made for 2023 with clues using only the numbers 2,3, and 23. The solution, a PDF version, and an easier version of the puzzle with more clues can all be found at: https://quadratablog.blogspot.com/2022/11/2023-new-years-puzzle.html
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Here's a fairly easy puzzle that I whipped up this morning, with clues based on the size of the products of the numbers in adjacent cells. The solution and a higher quality PDF version can be found at https://quadratablog.blogspot.com/.
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I recently posted a set-union puzzle so here's a new puzzle that uses set-intersections for clues. Info on set-intersections, the solution, a PDF version, and more information can be found at: https://quadratablog.blogspot.com/2022/10/intersections.html #mtbos #math #maths #puzzles #puzzle
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Here is a sudoku puzzle I made to commemorate my ten-year puzzle-creating anniversary. More info, a PDF version, and the solution can be found at: https://quadratablog.blogspot.com/2022/08/10th-anniversary-of-puzzle-creation.html
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My new puzzle today is based on sets and their unions. The small amount of set theory needed to try it can be found on my blog, along with the solution and PDF at this link: https://quadratablog.blogspot.com/2022/07/unions.html
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I was delighted to see that this month's Wolfram Blog entry by Matthew Sottile featured one of my chess puzzles from Math Horizons. You can find the article here:
https://blog.wolfram.com/.../solving-knightdoku.../
I figured readers might want to try some Knightdoku of their own, so I'm posting some new ones over at my blog. These are all meant to be solved for fun by humans without the aid of computers. One of them is posted above here. The other two can be found at my blog here:
https://quadratablog.blogspot.com/2022/04/wolfram-blog-and-quadratablog.html
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Enter 1 through 8 into the large circular cells so that each appears twice and adjacent cells contain different numbers. The clues between cells reveal the sum of those two cells. Numberless clues indicate that the sum is larger than eight without revealing that sum. Solution and more at: https://quadratablog.blogspot.com/2021/07/petersen-eight-graph-sum-puzzle.html
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This is a slightly larger variation of my last puzzle entry. Each row and each column contains 1 through 6 exactly once, but NO cage is allowed to contain all distinct numbers! Clues when given must equal the sum of the entries in that cage.
Solution and more info at: https://quadratablog.blogspot.com/2021/06/non-distinct-partition-puzzle.html
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Here's another calcudoku/KenKen style of puzzle but with a different twist. What if the entries in each cage are -forbidden- from being distinct? For example, a cage with three entries which add to 9 could be 4,4,1 but couldn't be 2,3,4, since those numbers are all different. Here are some small quick puzzles just to demonstrate the idea. All of the clues reveal the sums of the entries in that cage, but regardless of whether or not there is a clue, the entries in each cage cannot be distinct!
For the solution, a PDF, and more information, visit: https://quadratablog.blogspot.com/2021/05/mini-non-distinct-partition-puzzles.html
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Here are some small easy puzzles. Each row and column contains all the numbers 1 through 4, no cage contains duplicate numbers, and the numbers in a cage sum to a clue whenever a clue is given.
Solution, PDF, and more at:
https://quadratablog.blogspot.com/2021/05/mini-distinct-partition-puzzles.html
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New concept: Place 1 through 6 in the cells so each appears once in every row and column. The entries in each cage must be DISTINCT and sum to the clues when one is given. For more info visit: https://quadratablog.blogspot.com/2021/04/distinct-partition-puzzle.html
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